how do I show 12 numbers from a huge number?

[anabeatriz]

I have to look in my Math-book. Maybe there is a solution: http://weitz.de/KMFI/
The book is good, but it's only in German. He uses Python to explain math.

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With modular arithmetic you get the last x digits of the solution.
The built-in function pow supports it.

The equation is: 2 ** (2 ** 34)

pow(2, 2**34, 10**12)

This should calculate the last 12 digits of 2 ** (2**34)

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The other solution to get the first x digits can may be done with iteration.

def ipow(x, y, digits):
    for _ in range(y - 1):
        x *= x
        # do something to truncate x?
        # maybe working with math.log10

By the way, this question is very old: https://stackoverflow.com/questions/6351...e-required

Another solution is the usage of math.log10: https://stackoverflow.com/questions/3873...nentiation

def get_first_digits(a, b, n):
    x = b * math.log10(a)
    y = math.floor(pow(10, x - math.floor(x) + n - 1))
    return int(y)

Output:
In [65]: get_first_digits(2,2**34,12)                                                  
Out[65]: 927436539881

I showed these numbers yesterday to my teacher and he said they are not the correct ones. I have to buy a virtual machine soon to see the full number...