Replace last 4 bytes of a timestamp

[mPlummers]

Hello,

Can you try this?

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30

from datetime import datetime import math   old_date = "2019-08-06T07:37:51.358999986Z" print("old date: {}".format(old_date)) splited_date = old_date.split('.') old_date_without_milliseconds = splited_date[0] old_date_milliseconds = splited_date[1][:-1] print("old_date_without_milliseconds: {}".format(old_date_without_milliseconds)) print("old_date_milliseconds: {}".format(old_date_milliseconds)) new_bytes = [0xc8, 0xdc, 0xac, 0xa1] t = datetime.strptime(old_date_without_milliseconds, "%Y-%m-%dT%H:%M:%S") t = t.timestamp() print("Time stamp from old_date_without_milliseconds: {}".format(t)) t = int(t) * 1000000000 + int(old_date_milliseconds) print("Time stamp total * 1000000000: {}".format(t)) t = hex(t) print("Time stamp total in hex: {}".format(t)) size_new_bytes = len(new_bytes) * 2 t = t[:-size_new_bytes] for b in new_bytes:     t += hex(b)[2:] print("Time stamp in hex after substitution: {}".format(t)) t = int(t, 16) print("Time stamp after substitution: {}".format(t)) partie_entiere = math.floor((t / 1000000000)) * 1000000000 decimals = t - partie_entiere t = datetime.fromtimestamp(partie_entiere / 1000000000) t = datetime.strftime(t, "%Y-%m-%dT%H:%M:%S.") + str(decimals) + "Z" print("new date: {}".format(t))

Best Regards,

Nicolas TATARENKO

Hi Nicolas,

i'm back, i'm still stucked on this problem. But now i have an additional information: the new timestamps should differ from the others by a time close to 1 second. It's not always exactly a second, but it's a good way to test if the code works. Do you think this info may be useful to find out the solution? Also, with your code, sometimes the result is a timestamp with 1973 year, instead of 2019.
Thank you again for your support