Print different positions in loop from functions

[metulburr]

all you need to do is modify the print statement to insert the variables. You dont really need a function for an int as range() built-in returns a list of integers to the specified range.

>>> for x in range(1,5):
...     for y in range(1,5):
...             print(f'Hello{x} Bye{y}')
... 
Hello1 Bye1
Hello1 Bye2
Hello1 Bye3
Hello1 Bye4
Hello2 Bye1
Hello2 Bye2
Hello2 Bye3
Hello2 Bye4
Hello3 Bye1
Hello3 Bye2
Hello3 Bye3
Hello3 Bye4
Hello4 Bye1
Hello4 Bye2
Hello4 Bye3
Hello4 Bye4

You can add a newline to print a space between them

>>> for x in range(1,5):
...     for y in range(1,5):
...             print(f'Hello{x} Bye{y}\n')
... 
Hello1 Bye1

Hello1 Bye2

Hello1 Bye3

Hello1 Bye4

Hello2 Bye1

Hello2 Bye2

Hello2 Bye3

Hello2 Bye4

Hello3 Bye1

Hello3 Bye2

Hello3 Bye3

Hello3 Bye4

Hello4 Bye1

Hello4 Bye2

Hello4 Bye3

Hello4 Bye4

If you want the second number to always be 1 Bye1 then just ignore the nested loop y.

You can alternatively skip the nested for loop and use itertools.product

>>> from itertools import product
>>> r = range(1,5)
>>> for x,y in product(r,r):
...     print(f'Hello{x} Bye{y}')
... 
Hello1 Bye1
Hello1 Bye2
Hello1 Bye3
Hello1 Bye4
Hello2 Bye1
Hello2 Bye2
Hello2 Bye3
Hello2 Bye4
Hello3 Bye1
Hello3 Bye2
Hello3 Bye3
Hello3 Bye4
Hello4 Bye1
Hello4 Bye2
Hello4 Bye3
Hello4 Bye4