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Calculator math.sqrt
#1
So the main problem is im unsure how to implement math.sqrt into my code.
what i want is that i could take squareroot from answer i get. ive tried adding else to elseif but im doing something wrong so ill just paste working code as to not to confuse you.
import cmath
import math

# Program make a simple calculator that can add, subtract, multiply and divide using functions
# This function adds two numbers
def add(x, y):
   return x + y
# This function subtracts two numbers
def subtract(x, y):
   return x - y
# This function multiplies two numbers
def multiply(x, y):
   return x * y
# This function divides two numbers
def divide(x, y):
   return x / y
def sqareroot(x, y):
   return math.sqrt(x)

print("Select operation.")
print("1.Add")
print("2.Subtract")
print("3.Multiply")
print("4.Divide")
# Take input from the user
choice = input("Enter choice(1/2/3/4):")
num1 = int(input("Enter first number: "))
num2 = int(input("Enter second number: "))
if choice == '1':
   print(num1,"+",num2,"=", add(num1,num2))
elif choice == '2':
   print(num1,"-",num2,"=", subtract(num1,num2))
elif choice == '3':
   print(num1,"*",num2,"=", multiply(num1,num2))
elif choice == '4':
   print(num1,"/",num2,"=", divide(num1,num2))

else:
   print("Invalid input")
Reply


Messages In This Thread
Calculator math.sqrt - by GFreenD - Oct-28-2019, 12:58 PM
RE: Calculator math.sqrt - by ichabod801 - Oct-28-2019, 01:13 PM
RE: Calculator math.sqrt - by GFreenD - Oct-28-2019, 02:08 PM
RE: Calculator math.sqrt - by ichabod801 - Oct-28-2019, 02:20 PM
RE: Calculator math.sqrt - by jefsummers - Oct-28-2019, 08:01 PM

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