for any loop _ want to know which matches

[buran]

What am I doing wrong?

you misunderstood scidam's approach with regex
in slow motion:

import re

preset=r"cookie\."
list1=['cookie.A001', 'cookie.H004', 'cookie.H004 andsomeothertext', 'cookie.ABC031', 'cookie.FAIL002']
list2=['A', 'H', 'ABC']
list2_pats = map(lambda x: re.compile(preset + r'(%s)([0-9]+)' % x), list2)
result1 = [pat.findall(item) for pat in list2_pats for item in list1]
print('result1: {}\n'.format(result1))
result2 = sum(result1, [])
print('result2: {}\n'.format(result2))
result3 = zip(*result2)
print('result3: {}\n'.format(result3))
output1, output2 = result3
print('output1: {}\n'.format(output1))
print('output2: {}\n'.format(output2))

Output:
result1: [[('A', '001')], [], [], [], [], [], [('H', '004')], [('H', '004')], []
, [], [], [], [], [('ABC', '031')], []]

result2: [('A', '001'), ('H', '004'), ('H', '004'), ('ABC', '031')]

result3: [('A', 'H', 'H', 'ABC'), ('001', '004', '004', '031')]

output1: ('A', 'H', 'H', 'ABC')

output2: ('001', '004', '004', '031')

your line 10: if item in pat never will be True