phrase loop and character comparision

[shiro26]

from string import punctuation

def find_words(phrase, control):
    phrase = phrase.lower().split()
    words = [word.rstrip(punctuation) for word in phrase if word[0] < control]
    return words
    
my_phrase = "My pet is a Tiger; wild, white and with big eyes. Don't touch him."
     
print(find_words(phrase=my_phrase, control='n'))

['my', 'is', 'a', 'and', 'big', 'eyes', "don't", 'him']

Sorry for my late reply.
Thank you very much buran.
I understand from your quote that we can import the a punctuation package.
I am not familiar yet with 'rstrip' (just 'strip') so I will check it out.
Thank you again.
Shiro