Nested Functions

[ichabod801]

g returns h, which is the function h itself, not a call to the function. That's fine, that's the way you usually do it. But when you print(g), you are printing the function g itself, not the result of a call to g. That's why you need to do f(a)(b)(c). Let's step through it: f(a) returns g, so you get g(b)(c). g(b) returns h, so you get h(c), which returns 30.

You are using a, b, and c both globally and inside the function h. But the a, b, and c in h and not the global a, b, and c that you have defined globally. They are the a, b, and c that you set as parameters in the def statements, and they are whatever is passed to the function. That means that f(1)(2)(3) will give you 6. I don't know if that's what you're expecting.