How can I send error message to slack using webhook url in Python?

[PrateekG]

Hi All,

I have several Python functions. In case of any error I want to send the error message to slack. For this I have added below line of code in every except block -

except Exception as ex:
     msg = 'There is a problem with csv generation due to: {}'.format(ex)
     logger.info(msg)
     send_message("web_hook_url",msg)

Now I have written send_message() like below mentioned in this link webhook slack post

def send_message(webhook_url, message):
 response = requests.post(
     webhook_url, data=json.dumps(message),
     headers={'Content-Type': 'application/json'}
 )
 if response.status_code != 200:
     raise ValueError(
         'Request to slack returned an error %s, the response is:\n%s'
         % (response.status_code, response.text)
     )

But here I don't know how to use this function in my except block properrly. I am also not sure if it is written corrected.

So can anyone please look into this and help me?