List comparison in Python

[Vysero]

So the first element of "list a" ( e:g vlan 158" in this case ) has to be checked in "list b" and vice versa and if it is found then fine. If it is not found ( e:g vlan 159 ) is not available in "list a" then it should return everything i.e "list a " has below

When you say: "has to be checked in "list b"" are you meaning the first element of "list a" needs to be checked against the first element of each list in "list b"? S/T each matching instance can be ignored but none matching instances will result in a 'print' of the remaining elements in that list? For instance the program would for:

a = [['vlan 158', '  name MARKET', '  mode vpc'], []]
b = [['vlan 158', '  name MARKETING', '  mode vpc'], ['vlan 159', '  name SALES', '  mode vpc']]

produce the output:

#first element of list a matches first element of list b thus ignore
name SALES, mode vpc #first element of list a does not match second element of list b thus print
name MARKETING, mode vpc #second element in list a is an empty list thus will not match first element in list b thus print
name SALES, mode vpc #second element in list a is an empty list thus will not match second element in list b thus print