Avoid hard-coded folderPath in the code (let users provide it)

[snippsat]

I do agree with @Gribouillis
Can show both way,as you should have used os.path.join() in your first code.

from os import path

file_path = 'C:\\foo'  #input("Enter the file path: ")
file_name = 'test.txt'  #input("Enter the file name with extension (.txt): ")
full_path =  path.join(file_path, file_name)

print(f"Full file address is: {full_path}")

#---------------------------------------------

from pathlib import Path

file_path = Path('C:\\foo') #Path(input("Enter the file path: ").strip())
file_name =  'test.txt' #input('Enter the file name with extension (.txt): ').strip()
file_full_path = file_path / file_name
print("Full file address is", file_full_path)

Output:
Full file address is: C:\foo\test.txt
Full file address is C:\foo\test.txt

So the output is the "same" almost.
If look closer at it,so is the first one a string,
and second on a Path object that show it'a a Windows Path.

>>> full_path
'C:\\foo\\test.txt'

>>> file_full_path
WindowsPath('C:/foo/test.txt')

What if need that Path object should be a string?
The right way is to use os.fspath(path) and not str.

>>>import os

>>> os.fspath(file_full_path)
'C:\\foo\\test.txt'

>>> # Can also to it without import 
>>> file_full_path.__fspath__()
'C:\\foo\\test.txt'