Sep-20-2018, 02:34 AM
soup.find.a['href']
will get the link. If that is the link then you will just have to parse it out of the string manually.
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python3 BS4 help
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Messages In This Thread |
python3 BS4 help - by freaknez - Sep-19-2018, 11:55 PM
RE: python3 BS4 help - by metulburr - Sep-20-2018, 02:34 AM
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