Stopping scheduler with condition

[j.crater]

Hello,
I need to execute some code repeatedly with a fixed interval. I scraped this piece of code online:

class PeriodicScheduler(object):
    def __init__(self):
        self.scheduler = sched.scheduler(time.time, time.sleep)

    def setup(self, interval, action, actionargs=()):
        action(*actionargs)
        self.event = self.scheduler.enter(interval, 1, self.setup, (interval, action, actionargs))

    def run(self):
        self.scheduler.run()

    def stop(self):
        self._running = False
        if self.scheduler and self.event:
            self.scheduler.cancel(self.event)


# This is the event to execute every time
def periodic_event():
    print("hello")

# Start the scheduler
INTERVAL = 1
periodic_scheduler = PeriodicScheduler()
periodic_scheduler.setup(INTERVAL, periodic_event)  # it executes the event just once
periodic_scheduler.run()  # it starts the scheduler

The code works fine, it prints "hello" every second. I must say I never used schedulers before and so far didn't study the shown code deeply, so I don't fully understand how it works. But I would like to modify it so that the scheduled event only executes a given number of times.

My attempt was to add a counter variable inside periodic_event(), make checks (e.g. if cnt < 10), and if condition is satisfied call periodic_scheduler.stop(). But I couldn't make it work with all the scope errors I got. So I believe the approach wasn't a good one and there is probably a more obvious, standard solution, that I am not aware of.

What do you suggest me to do in this case? Did I even take the right direction in achieving the goal (executing a function specific number of times with fixed interval)?
Thank you,
JC