The int that appears an odd number of times.

[MeeranRizvi]

i did with dictionary

a = [1,2,3,2,4,2,4,3,5,5,1]
result = dict((i, a.count(i)) for i in a)
print result

I just got the counts but how to print only the int that appears an odd no of times

Output:
{1: 2, 2: 3, 3: 2, 4: 2, 5: 2}