Help with try and open 6.txt file and print as perfect or not

[Pleiades]

Have you tried xrange() yet?

With this number: 191561942608236107294793378084303638130997321548169216
Hi nilamo,

Thanks for the quick response. This is the new error with xrange.

Traceback (most recent call last):
File "C:\Python27\perfect numbers cheker.py", line 24, in <module>
for pair in factor_number(number):
File "C:\Python27\perfect numbers cheker.py", line 16, in factor_number
return [(x, n // x) for x in xrange(1, root + 1) if n % x == 0]
OverflowError: Python int too large to convert to C long

import math

 
KB = 1024
MB = 1024 * 1024
 
def perfect_number(number, factors):
    sum_of_factors = sum(factors) - number
    if sum_of_factors == number:
        return "The number {} is a Perfect number!".format(number)
    else:
        return "The number {} is not a Perfect number!".format(number)
 
def factor_number(n):
    root = int(round(math.sqrt(n), 0))
    return [(x, n // x) for x in xrange(1, root + 1) if n % x == 0]
 
if __name__ == '__main__':
    with open('6.txt', buffering=1*MB) as bigggg:
        for num in bigggg:
            number = int(num)
            factors = []
 
            for pair in factor_number(number):
                factors.extend(pair)
 
            print(perfect_number(number, factors))
 
    factors = []
 
    for pair in factor_number(6):
        factors.extend(pair)
 
    print(perfect_number(6, factors))

---

nilamo,

2**19-1*(2**18) works

The number 137438691328 is a Perfect number!