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catching / handle index out of range
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catching / handle index out of range
#1
Guys,

Back again, fiddling with an 'index out of range' thingy. To my (limited) knowledge this is how I would do it.

Your thoughts?
a = [1,2,3]
b = [1]
c = [1,4,5,6]
d = [1,2,3]

e = [a,b,c,d]
index_needed = 2
output = [item[index_needed] for item in e if len(item) > index_needed]

print(output)
# outputs 3, 5, 3
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Messages In This Thread
catching / handle index out of range - by 3Pinter - Feb-04-2019, 11:36 AM
RE: catching / handle index out of range - by buran - Feb-04-2019, 01:19 PM

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