Streamline this format code

[birdieman]

I fixed it. This is what I used (in the above example):

nums2 = tuple('${:,.0f}'.format(num).rjust(12, ' ') for num in nums)
print(hdr62.format(*nums2))

Is that solution efficient?

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Another solution, but better (I think) because no need to make another tuple:

print(hdr62.format(*['${:,.0f}'.format(n) for n in nums]))