Division of an integer into sub-numbers

[DeaD_EyE]

If you want to use math, you can do following:

1. Get the digits of the number with math.log10
   
2. Convert the result of digits to integer
   
3. In a for-loop with reversed(range(digits + 1))
   
4. Each iteration give you a integer (large > 0), which should be the position of the digt.
   
5. Integer division: big_number // 10**digits
   
6. Use modulo, to get only one digit: result = result % 10
   

The implementation, of what I described:

def split_numbers(number):
    digits = int(math.log10(number))
    for d in reversed(range(digits + 1)):
        digit = (number // 10 ** d) % 10
        yield digit

Much easier is following code:

def split_digits(number):
    return [int(d) for d in str(number)]

The number could be a int or a str.
Math is not used. I use the fact, that str is iterable. If you
iterate over a str you'll get char by char.



+If you want to check, if a number is really an integer, use exceptions:

try:
    big_number = int(big_number_as_str)
except ValueError:
    print('Is not a int')
else:
    print('Is a int')
    print(big_number)

In Python a complex consists of two floats. One float for the real part, one float for the imaginary part.
Floats do have the method is_integer(), so you can test also, each part of the complex if it's an integer.