zip file variable prints <zipfile.ZipFile object at 0x7f83fd13bd90> ?

[heiner55]

The zipfile itself should be outside of "server1".
To zip the directory "server1", you have to loop over the files.

!/usr/bin/python3
import os, zipfile

server1 = "test"
log_file_name = "logfile"

zip_file = zipfile.ZipFile(log_file_name + ".zip", "w")
for dirname, subdirs, files in os.walk(server1):
    for filename in files:
        zip_file.write(os.path.join(dirname, filename))
zip_file.close()