Counting number of occurrences of a single digit in a list

[python_newbie09]

is it what you're looking for?
(just adapt to your case)

n = 600;
A = np.random.randint(100, size = (n,1), dtype = np.int);
loc = np.where(A == 85);
loc_exact = list(loc)[0];

Thanks but it doesn't quite achieve what I am looking for. It is tricky because if I adapt this code, the result I will get is 6 occurrences of 85 instead of 2 occurrences. I am still thinking :|