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Counting number of occurrences of a single digit in a list
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Counting number of occurrences of a single digit in a list
#13
If I understand the task at hand correctly then groupby can be used:

>>> data = [0,1,1,1,1,2,2,2,85,85,85,80,80,80,0,1,1,1,2,2,2,85,95,80,80,80]
>>> [[*group][0][0] for match, group in groupby(enumerate(data), key=lambda digit: digit[1] == 85) if match == True]
[8, 21]   # index of first 85 in group
EDIT:
If groups are large then indices can be obtained without unpacking next(group)[0]
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RE: Counting number of occurrences of a single digit in a list - by perfringo - Aug-12-2019, 01:31 PM

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