String handling

[YoungGrassHopper]

In a ordinary loop it would be like this.

>>> string = 'The quick brown fox jumps over the lazy dog. '
>>> characters = 'aeiou'
>>> 
>>> lst = []
>>> for c in string:
...     if c not in characters:
...         lst.append(c)
...         
>>> print(''.join(lst))
Th qck brwn fx jmps vr th lzy dg.

So a list comprehension construct make code over in line.

Can also remove the list as it's make a generator object first.

>>> g = (c for c in string if c not in characters)
>>> g
<generator object <genexpr> at 0x03C8C8B0>

>>> next(g)
'T'
>>> next(g)
'h'

See that there is a small difference no [],and it still work as ''.join() run the generator expressions.

>>> print(''.join(c for c in string if c not in characters))
Th qck brwn fx jmps vr th lzy dg. 

Thanks snippsat
The ordinary loops is much softer on my understanding as I have only worked with a couple of them till date and haven't been taught or tasked to use a for loop as a one liner. the one liners though look more simple as there seems no need for indentation and all that.

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Since this thread is named string handling and the use of for loops are being discussed.
I have another task bugging me which I need advice on.

So I have a txt file with a list of names surnames and date of births.
it looks like this:

Orville Wright 21 July 1988
Rogelio Holloway 13 September 1988
Marjorie Figueroa 9 October 1988
Debra Garner 7 February 1988

And so on.

I need to write python code which reads in the data from the list and restructures and prints it in this format:

Name:
Debra Garner    

Birthdate:
7 February 1988

My attempt :

f = open
doc = f.read()
print(doc.replace(' ','\n'))
f.close()                                                                                                             

Now I am getting:

Debra
Surname
21
Aug
1999


Is it possible to refer to the second white space in a line or how would one efficiently go about solving this?