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Numpy structured array
#4
OK. Not as a function but this does the trick, modify as needed at accept an argument and as a function and you've got it.
import numpy as np

a = np.array([(b'FRA',  50.026,    8.543), (b'DEN',  39.862, -104.673),
       (b'BKK',  13.681,  100.747), (b'SYD', -33.946,  151.177),
       (b'GRU', -23.432,  -46.47 ), (b'CLT',  35.214,  -80.943),
       (b'SFO',  37.619, -122.375), (b'IAH',  29.984,  -95.341),
       (b'ATL',  33.637,  -84.428), (b'ICN',  37.469,  126.451),
       (b'DFW',  32.897,  -97.038), (b'HND',  35.552,  139.78 ),
       (b'LAS',  36.08 , -115.152), (b'PHX',  33.434, -112.012),
       (b'PVG',  31.143,  121.805), (b'DXB',  25.253,   55.364),
       (b'MIA',  25.793,  -80.291), (b'IST',  40.977,   28.815),
       (b'AMS',  52.309,    4.764), (b'CAN',  23.392,  113.299),
       (b'LAX',  33.943, -118.408), (b'CGK',  -6.126,  106.656),
       (b'LHR',  51.477,   -0.461), (b'JFK',  40.64 ,  -73.779),
       (b'SIN',   1.35 ,  103.994), (b'CDG',  49.013,    2.55 ),
       (b'HKG',  22.309,  113.915), (b'ORD',  41.979,  -87.905),
       (b'KUL',   2.746,  101.71 ), (b'PEK',  40.08 ,  116.585)],dtype=[('IATA', 'S4'), ('latitude', '<f8'), ('longitude', '<f8')])

for obj in a:
    better_list = list(obj)
    if better_list[0] == b'BKK' :
        print(f"Foo = {better_list[1]}")
Reply


Messages In This Thread
Numpy structured array - by Nitram - Sep-17-2019, 12:02 PM
RE: Numpy structured array - by jefsummers - Sep-17-2019, 06:00 PM
RE: Numpy structured array - by Nitram - Sep-17-2019, 07:17 PM
RE: Numpy structured array - by jefsummers - Sep-17-2019, 10:09 PM

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