Partial "visual" Matching of matrices

[masteripper]

Well thanks for the responses
With your help i have constructed the following (Pandas is great !!! )

import pandas as pd

def noOfDifferentElements(matrix1,matrix2):
    pinput1 = pd.DataFrame(matrix1)
    pinput2 = pd.DataFrame(matrix2)
    dfBool = (pinput1 != pinput2).stack()
    diff = pd.concat([pinput1.stack()[dfBool],pinput2.stack()[dfBool]],axis=1)
    print("No of Differece Matrix1 & Matrix2 : {difference}".format(difference=diff.size/2))

# converting your input data to a valid Python object:
A = """
1 0 1 1 1 0 0 1
1 0 0 1 1 0 0 1
1 0 1 0 0 0 0 0
1 0 0 0 1 0 0 1
""".strip()

B = """
0 1 0 0 1 0 0 1
1 1 0 0 0 0 0 1
1 1 1 0 0 0 0 1
1 0 1 0 1 0 0 1
""".strip()

C = """
1 0 1 0 1 0 0 1
1 0 1 1 1 0 0 1
1 0 1 0 0 0 0 1
1 1 0 0 1 0 0 1
""".strip()

# nested list comprehension to create the matrix
a = [[int(d) for d in a.split()] for a in A.splitlines()]
b = [[int(d) for d in b.split()] for b in B.splitlines()]
c = [[int(d) for d in c.split()] for c in C.splitlines()]


# Testing No of Differences between of the matrices
noOfDifferentElements(a,b)
noOfDifferentElements(b,c)
noOfDifferentElements(a,c)

and the winner is :

No of Differece Matrix1 & Matrix2 : 10.0
No of Differece Matrix1 & Matrix2 : 10.0
No of Differece Matrix1 & Matrix2 : 4.0