capture next block of text after finding error in file

[buran]

error.log

Output:
2019-11-18 01:46:47:INFO:3496839:/var/logs/apc/ : no errors detected.
2019-11-18 01:46:47:INFO:3496839:/var/logs/xyz/ : no errors detected.
2019-11-18 01:46:47:ERROR:3496839:check reported errors in the /var/logs/jkl/ database.  These should be rechecked to verify if the errors are accurate.
2019-11-18 01:46:47:ERROR:3496839:check reported errors in the /var/logs/jkl/spam database.  These should be rechecked to verify if the errors are accurate.

using just str methods

log_file = 'error.log'

with open(log_file) as lf:
    for line in lf:
        log_date_hour, log_minute, log_seconds, log_type, some_code, info, *rest = line.split(':')
        if log_type == 'ERROR':
            print(info.split(' ')[5])

Output:
/var/logs/jkl/
/var/logs/jkl/spam

using regex

import re
regex = re.compile(r'reported errors in the (?P<path>\S*)', flags=re.MULTILINE)
with open(log_file) as lf:
    logs = lf.read()

paths = regex.findall(logs)
print(paths)

Output:
['/var/logs/jkl/', '/var/logs/jkl/spam']

if file is huge it may be better to read it line by line (like in first example and use regex to parse the line). maybe it's possible to make better regex pattern though

also both snippets will fail if there is space in the path. if you expect these you may have to adjust the code accordingly