[Tkinter] Tkinter problem

[catlessness]

1.if you just run this, youll have a window to input 'order' and 'Rs'.
2.Enter a number in 'order' and press ok.
3.Change the number in 'order' again and press ok again.
youll know what wrong's with it.

QUESTIONS:

First: how can i cover these elements created by clicking 'ok'?
Second: is there any way that i dont have to have a button but show the elements right after i enter a number in 'order'

Thank you!!!!

import tkinter as tk
R=[]
C=[]
order=0
# GUI
def GUI():
    window=tk.Tk()
    window.title('variable assignment')
    window.geometry('500x600')
    order_label=tk.Label(window,text='order',font=(14))
    order_label.pack()
    order_msgbx=tk.Entry(window,show=None)
    print(type(order))
    order_msgbx.pack()
    R_s_label=tk.Label(window,text='Rs',font=(14))
    R_s_label.pack()
    R_s_msgbx=tk.Entry(window,show=None)
    R_s=R_s_msgbx.get()
    R_s_msgbx.pack()
    R_msgbx=[]
    C_msgbx=[]
    R_label_list=locals()
    C_label_list=locals()

    def RC_button():
        order=int(order_msgbx.get())
        print(order)
        window=tk.Tk()
        if order>0:
            for n in range(order):
                R_label_list['R_label_' + str(n+1)] = tk.Label(window,text='R'+str(n+1),font=(14))
                R_label_list['R_label_' + str(n+1)].pack()
                R_msgbx0=tk.Entry(window,show=None)
                R_msgbx.append(R_msgbx0)
                R_msgbx[n].pack()
                R.append(R_msgbx[n].get)
                C_label_list['C_label_' + str(n+1)] = tk.Label(window,text='C'+str(n+1),font=(14))
                C_label_list['C_label_' + str(n+1)].pack()
                C_msgbx0=tk.Entry(window,show=None)
                C_msgbx.append(C_msgbx0)
                C_msgbx[n].pack()
                C.append(C_msgbx[n].get)
    RC_button=tk.Button(window, text='OK',width=15,height=2,command=RC_button)
    RC_button.pack()
    window.mainloop()
GUI()