Lists union and intersecion

[buran]

This is one way to do it

# convert to sets
result = set(dia).union(set(mots))
print(result)
print(list(result))
 
result2 = set(dia).intersection(set(mots))
print(result2)
print(list(result2))

However, this will not preserve order and set have unique elements, so if there are duplicates in the list (same element more than one time in list) they will be lost


And this is working with lists - order and repeating elements are preserved

# if order is imporatnt
result = [element for element in dia if element in set(mots)] # this is list comprehension, but it can be replaced by regular loop
print(result)
 
dia.extend(mots)
print(dia)