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min() function in iterable index
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min() function in iterable index
#1
Hi,
For a choice of 4 letters (a, b, c, d) for example, a sequence of letters is displayed, arranged as follows:
Output:
aaaaaaa abbbbba abcccba abcdcba abcccba abbbbba aaaaaaa
with this code:

alphabet =['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
 
choice =int(input())
 
size =choice *2 -1
line =0
for _ in range(size):
      column =0
      for _ in range(size):
            print(alphabet[min(min(line, size -1 -line), min(column, size -1 -column))], end ='')
            column +=1
      line +=1
I like this approach but I can't quite grasp the use of the min () function, the mechanism escapes me completely in this program.
Could someone please explain to me how the min() function works in this case?
Reply


Messages In This Thread
min() function in iterable index - by OokaydO - Apr-17-2020, 09:24 PM
RE: min() function in iterable index - by OokaydO - Apr-18-2020, 08:57 PM
RE: min() function in iterable index - by OokaydO - Apr-23-2020, 09:21 AM

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