Python 2 to 3 dict sorting

[DeaD_EyE]

Funny, I even did not know that you can't do that.
But there is a solution. You can use the key-function to convert
the keys to a tuple or list. Then this object is used for comparison.

sorted([{-21: None, 2: None}, {-100: None, -2: None}], key=lambda x: tuple(x.keys()))

The key-function can also written as normal function:

def dict_sort(mapping):
    return tuple(mapping.keys())

sorted([{-21: None, 2: None}, {-100: None, -2: None}], key=dict_sort)

You can also choose a key, which you want to use for sorting or you can select values to sort the dict.
It depends on what you want to reach.