if the input is not number, let user input again

[ibutun]

Another way. Modified code a little.

#! /usr/bin/env python3.8

while True:
    try:
        my_name = input('What is your name: ')
        if my_name.isdigit():
            print(f'{my_name} is a number. Please use letters for a name.')
            continue
        else:
            print(f'Your name is {my_name}. It\'s nice to meet you')
            print(f'The length of your name is {len(my_name)} letters.')
            break
    except ValueError as error:
        print(f'Error: {error}')
        break

while True:
    try:
        my_age = input('What is your age: ')
        if my_age.isalpha():
            print(f'{my_age} is not allowed in age')
            continue
        else:
            age = int(my_age) + 1
            print(f'You will be {age} next year.')
            break
    except ValueError as error:
        print(f'Error: {error}')
        break
print(f'{my_name.title()} will be {age} next year.')

Friend i want to do like this... Thank you I understood the working logic of some codes like x.isalpha(): , y.isdigit():, while loop must be end with except code, and also When the application is finished, we have to use the "break" command to switch to the other application.

But i ask another question
this programme work perfect but when i enter my name like 15.1 (float) is says:

Output:
What is your name: 15.1
Your name is 15.1. It's nice to meet you
The length of your name is 4 letters. 

is this float is not a digit ?