Problem with comparing list

[DeaD_EyE]

list_b is shorter. Checking if all elements of list_b are in list_a:

list_a = [25,15,40,40,10]
list_b = [40,40,10]

if all(b in list_a for b in list_b):
    print('All elements of list_b are in list_a')
else:
    print('Not all elements of list_b are in list_a')

If you use the set theorie, it's easier:

list_a = [25,15,40,40,10]
list_b = [40,40,10]
if set(list_b).issubset(list_a):
    print("set_b is a subset of set_a")
else:
    print("set_b is not a subset of set_a")

A set contains only unique elements.
The order of elements is not preserved.