Get the filename from a path

[12237ee1]

I am using linux so where should I put the path of the file in the script
I tried it like this
a= "/home/file.txt"
pdf_files = set(a)
but it didn't work .. also I need the result without brackets only the name of one file in each line
thank you

Usually you save your data in your homedirectory.

If your username is 12237ee1, then path to your home directory is: /home/12237ee1/. Put your file into your home directory. If you open your terminal window, you're already loged in with your user. Use pwd to show the Path where you are.

Applying the set on a regular str does not what you want:

In [1]: set("/home/file.txt")                                                                                                
Out[1]: {'.', '/', 'e', 'f', 'h', 'i', 'l', 'm', 'o', 't', 'x'}

You need the lines in a sequence and then you can consume them with a set.

with open("/home/12237ee1/file.txt") as fd:
    unique_lines = set(fd)

fd is an iterator, which yields lines (with line ending).
The set() takes those elements. Identical lines are removed and the order is not preserved.

But these are the basics. You need to know what a file object is, what iterables are and what the different data types does with it.
Otherwise, you'll not understand how Python works. I call it brute-force programming, what you do.

how to do it with split() beacuse yes these's more than one link in one line ? in another word how to only print the name between "/" and ".pdf" while including the ".pdf"
if you can put all the script in one box so I can understand better .. thank you again