Scrape for html based on url string and output into csv

[snippsat]

Look at content you get back,eg print(soup).

<noscript>This '
 'site requires Javascript to work,.....

So i don't know if just test this on a server(that make this more difficult) that may not be needed for this this task.
Usually when a site use a lot of Javascript can use Selenium

As this is just a simple test of a server that not may be needed for this task,can bypass it be passing in the cookie.

from bs4 import BeautifulSoup
from requests import get

page = "http://py123.epizy.com/index.html"
headers = {'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_10_1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/39.0.2171.95 Safari/537.36'}
cookies = {'__test': '1bb6e881021f013463740eeb74840b18'}
content = get(page, headers=headers,  cookies=cookies).content
soup = BeautifulSoup(content, "lxml")

table_info = soup.select_one('.table-info')
mail = table_info.select_one('.col-2 a')
mail = mail.get('href')
mail_clean = mail.split(':')[1]
print(mail_clean)

Output:
[email protected]