Giving all possible values to four different variables

[deanhystad]

Use integer 0 through 10 and convert to float when the values are used.

import itertools
four = []
for a, b, c in itertools.product(range(11), repeat=3):
    if (d := 10 - a - b - c) >= 0:
        four.append([a, b, c, d]) # <- Can convert to float here or when used

This code generates 1331 combinations of which 286 are valid.

If you want to be really efficient you can do this:

for a in range(11):
    for b in range(11-a):
        for c in range(11-a-b):
            four.append([a, b, c, 10-a-b-c])

The inner loop executes 286 times to give you the 286 possible number combinations.