Group List Elements according to the Input with the order of binary combination

[bowlofred]

Your information is already stored in the list variables. I wouldn't move the data to other names.

Maybe something like this?

from itertools import product
from more_itertools import grouper
import string

# create the "data"
number_pairs = 3
variables = list(string.ascii_uppercase[:number_pairs * 2])
print(f"variables data starts as {variables}")

number = len(variables)

groups = grouper(variables, 2)
finallist = product(*groups)
print(list(finallist))

Output:
variables data starts as ['A', 'B', 'C', 'D', 'E', 'F']
[('A', 'C', 'E'), ('A', 'C', 'F'), ('A', 'D', 'E'), ('A', 'D', 'F'), ('B', 'C', 'E'), ('B', 'C', 'F'), ('B', 'D', 'E'), ('B', 'D', 'F')]

Change number_pairs make a bigger list, and the the product is created from whatever is in the list.