Group List Elements according to the Input with the order of binary combination

[bowlofred]

Show the entire code (including imports). Your code seems to work for me....

import itertools
import more_itertools

number =2
for variables in itertools.product([0, 1], repeat=(number*2)): # set of variables for a,ap,b,bp,c,cp like 000000 000001 000011....
    #a,ap,b,bp,c,cp= variables[0],variables[1],variables[2],hvariables[3] #giving value for a,ap,b,bp,c,cp
    #nlist = [(a,b),(a,bp),(ap,b),(ap,bp)] #binary combination of a,ap,b,bp,c,cp
    groups = more_itertools.grouper(variables, 2)
    finallist = itertools.product(*groups)
    print(list(finallist))

Output:
[(0, 0), (0, 0), (0, 0), (0, 0)]
[(0, 0), (0, 1), (0, 0), (0, 1)]
[(0, 1), (0, 0), (0, 1), (0, 0)]
[(0, 1), (0, 1), (0, 1), (0, 1)]
[(0, 0), (0, 0), (1, 0), (1, 0)]
[(0, 0), (0, 1), (1, 0), (1, 1)]
[(0, 1), (0, 0), (1, 1), (1, 0)]
[(0, 1), (0, 1), (1, 1), (1, 1)]
[(1, 0), (1, 0), (0, 0), (0, 0)]
[(1, 0), (1, 1), (0, 0), (0, 1)]
[(1, 1), (1, 0), (0, 1), (0, 0)]
[(1, 1), (1, 1), (0, 1), (0, 1)]
[(1, 0), (1, 0), (1, 0), (1, 0)]
[(1, 0), (1, 1), (1, 0), (1, 1)]
[(1, 1), (1, 0), (1, 1), (1, 0)]
[(1, 1), (1, 1), (1, 1), (1, 1)]