Order a list with successive permutations based on another list

[yvrob]

Hi everybody,

I am running into a problem that seems rather simple but here is what I need to do:
I have an initial list, say: L = [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
I have an order list, say: o = [9 ,1 ,2 ,5 ,7 ,3 ,10 ,8 , 4, 6]

My goal is to sort L based on the order list. So for my simple listL, it would become the same as o.
Where the difficult comes is that I would like to do that only by swapping members of the list L.

My attempt to do that was the following:

for i in range(len(l)):
    print('Swapping {} and {}'.format(i+1, order[i]))
    tmp = l[i]
    l[i] = l[order[i]-1]
    l[order[i]-1] = tmp
    print(l)

The problem is that what I end up with for this simple example is [ 2, 3, 6, 1, 7, 4, 10, 8, 5, 9]

Would you have any suggestion? I really need to keep the swapping part.

Thanks!