remove vowels in word with conditional

[ambrozote]

Hello,

I am trying to shorten large strings by applying some rules to it but not being able to figure it out.

Here is the code I have tried so far w/o success.
The string in endString is my end goal using the startString sample.
The rules are added as comments below.

Thank you in advance for your help

startString = "Masonry - Concrete Block (Small) - Misc Air Layer - Insulation - Aluminium"
endString = "Msnr-CncrBlck(Smll)-MiscAirLyr-Insltn-Almnm"

#rules
#words => 4 chars are left untouched
#words > 4 chars have all lowercase vowels removed
#special chars are kept, such as parenthesis and hyphens

words = startString.split()

for index in range(len(words)):
    if len(words[index]) > 4:
        vowels = ('a', 'e', 'i', 'o', 'u')
        for x in words[index]:
            if x in vowels:
                shorter = words[index].replace(x, "")

endStringByCode = "".join(shorter)
print (endStringByCode)