Compile list of dictianories out of another list of dictianories by certain keys

[Caprone]

Maybe I am missing something but it seems that simple filtering functions would do. Something like:

lod = [{"id": 1, "a": 1, "b": 2, "result": 9.82},
       {"id": 2, "a": 1, "b": 2, "result": -5},
       {"id": 3, "a": 1, "b": 5, "result": 7.98}]

def filter_dicts(data, *args, **kwargs):
    for row in data:
        for k, v in kwargs.items():
            if row[k] != v:
                break
        else:
            yield {key: row[key] for key in args}

print(*filter_dicts(lod, 'id', 'result', a=1, b=2))

# will print -> {'id': 1, 'result': 9.82} {'id': 2, 'result': -5}

this is a good solution but not a pythonic solution;
You should always try to avoid nested loop where possible and take advantage of list/dict comprehension;
and more --> try to simplify the problem -->
in this case You only need to know if kwargs' dict is a subset of the 'row' dict (as constraint made by OT) , no checking loop needed:

def filter_dicts(data, *args, **kwargs):
   return  ({key: row[key] for key in args}  for row in data  if row.items() >= kwargs.items())