Extract Href URL and Text From List

[knight2000]

Use textand attrs.
Don't use findAll('a')(will be a list) in loop just find('a')
Also use find_all('a'),the old CamleCase(do not use in Python) is kept for backward compatibility.

>>> from bs4 import BeautifulSoup
>>> 
>>> html = '<a href="/vdi-software/">VDI Software</a>'
>>> soup = BeautifulSoup(html, 'lxml')
>>> tag = soup.find('a')
>>> tag
<a href="/vdi-software/">VDI Software</a>
>>> 
>>> tag.text
'VDI Software'
>>> tag.attrs.get('href', 'Not found')
'/vdi-software/'
>>> tag.attrs.get('car', 'Not found')
'Not found'

Hi snippsat,

Thanks so much for helping out and teaching me. Also appreciate you pointing out better practices re- find_all. Awesome to learn new stuff!