[SOLVED] Find last occurence of pattern in text file?

[Winfried]

It's just a ~100KB file, so it fast enough.

I simplified the script with a function:

import re
#pip install pyperclip
import pyperclip

def SearchAndTell(MYFILE,mypattern):
	p = re.compile(mypattern)
	for line in reversed(open(MYFILE).readlines()):
		m = p.search(line.rstrip())
		if m:
			return m.group(1)
			break #needed?

INPUTFILE = "log.txt" 
clipb = None

pattern = "^START_A.+to (.+?) \(.+$"
clipb = f"-ss {SearchAndTell(INPUTFILE,pattern)} ".replace(",",".")
pattern = "^START_B.+to (.+?) \(.+$"
clipb += f"-to {SearchAndTell(INPUTFILE,pattern)}".replace(",",".")

pyperclip.copy(clipb)

FWIW, here's the batch script:

grep -Poha "^START_A.+$" log.txt | sed -r "s@^.+ to (.+?) \(.+$@-ss \1@" | sed -r "s@,@.@g" | tail -1
grep -Poha "^START_B.+$" log.txt | sed -r "s@^.+ to (.+?) \(.+$@-to \1@" | sed -r "s@,@.@g" | tail -1