Simple code question about lambda and tuples

[JasPyt]

I have a simple code:

my_tuple = (0,1,2,3,4,5,6)
foo = list(filter(lambda x: x-0, my_tuple))

print(foo)

I know what the output is and that it removes the first entry, the 0. I could also change it as follows:

my_tuple = (0,1,2,3,4,5,6)
foo = list(filter(lambda x: x-0 and x-1, my_tuple))

print(foo)

I thought that tuples are immutable? How are the 0 and 1 removed? How does this work and what is this x-0 actually doing?

Yoriz write Oct-03-2021, 02:22 PM:
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