Oct-12-2021, 02:29 PM
Dear DeanHystad,
you are absolutely right with your answer.
I checked it in the the source code.
b = Figure() : is a figure in memory only
a = plt.figure() : is a same figure but linked to a canvas (screen frame buffer)
you are absolutely right with your answer.
I checked it in the the source code.
b = Figure() : is a figure in memory only
a = plt.figure() : is a same figure but linked to a canvas (screen frame buffer)