Numeric Anagrams - Count Occurances

[monty024]

Greetings,

I am new to Python and messing around with a script with that will read a text file. Each line in the text file contains a three digit number from 000 to 999, the number of lines in the text file can vary. The script I made counts the number of occurrences for each number. However what I want to expand that and get the numeric anagram count.
For example if I have the list as shown below:

123
132
750
213
231
312
321
123
990
570

i would like the output to be:
(123,132,213,231,321,312) = 7
(099,909,990) = 1
(057, 075, 507, 570, 705, 750) = 2


This is the code I have to count the occurrences of a number. I know it can be cleaned up a but I am still just learning and will figure out how to clean it up, but I just need help with the code for the numeric anagram portion. I have searched the forum but only came across word anagram code. Any help would be greatly appreciated.

Regards,
Monty

for occurance in range(000, 100):
    file = open("/home/monty/Documents/Python_Projects/Book1-new.txt", "r")
    data = file.read()
    occurance_fill = f"{occurance:03d}"
    occurances = data.count(str(occurance_fill))

for occurance2 in range(100, 1000):
    file = open("/home/monty/Documents/Python_Projects/Book1-new.txt", "r")
    data = file.read()
    occurance2_fill = f"{occurance2}"
    occurances = data.count(str(occurance2_fill))
    print(str(occurance2_fill) + " : " + str(occurances))