Why is the if construct not calculating correctly?

[Larz60+]

once the if is satisfied, the remaining chain of elif's will not get executed. That's the way that it is intended.

If you want each statement to be executes, use a list of if's
the else is not necessary as you initialize sum to 0 before starting
Now, since sum is replaced each time, sum will be overwritten by the last successful if statement.

example:

def method1(e8, e13, e21, e55):
    sum = 0

    print(f"\nmethod1")

    if (e8 > e13):
        print(f"e8 > e13, so I'm done")
        sum = 1
    elif (e8 < e13):
        print(f"e8 < e13, so I'm done")
        sum = 0
    elif (e13 > e21):
        print(f"e813 > e21, so I'm done")
        sum = 1
    elif (e13 < e21):
        print(f"e13 < e21, so I'm done")
        sum = 0
    elif (e21 > e55):
        print(f"e21 > e55, so I'm done")
        sum = 1
    print(f"sum: {sum}")

def method2(e8, e13, e21, e55):
    sum = 0

    print(f"\nmethod2")
    if (e8, e13, e21, e55):
        print(f"e8 > e13")
        sum = 1
    if (e8 < e13):
        print(f"e8 < e13")
        sum = 0
    if (e13 > e21):
        print(f"e813 > e21")
        sum = 1
    if (e13 < e21):
        print(f"e13 < e21")
        sum = 0
    if (e21 > e55):
        print(f"e21 > e55")
        sum = 1
    print(f"sum: {sum}")

def main():
    method1(e8 = 1, e13 = 10, e21=6, e55 = 4)
    method2(e8 = 1, e13 = 10, e21=6, e55 = 4)

if __name__ == '__main__':
    main()

Output:
method1
e8 < e13, so I'm done
sum: 0

method2
e8 > e13
e8 < e13
e813 > e21
e21 > e55
sum: 1

which is what should be expected.