accept command line argument

[carecavoador]

Hi Team,

how to accept multiple values or a list of values from command prompt. and store into single variable.

folderpath, next list of file names to delete.

accept "ab,xy,py,cd,ef,gh" and store into single variable.

**python test.py "C:/Users/malle/OneDrive/Desktop/C/test_data" "ab,xy,py,cd,ef,gh"**

from pathlib import Path
import sys

def remove_files(folderpath, files):
    import os
    os.chdir(folderpath)
    collection = []
    collection = files.split(",")
    for coll in collection:
        files = Path.cwd().glob(f"*{coll}*")
        for file in files:
            file.unlink(missing_ok=True)
	

if __name__ == "__main__":
    pattern = "ab,xy,py,cd,ef,gh"
    root = "C:/Users/malle/OneDrive/Desktop/C/test_data"
    remove_files(root, pattern)

You could use sys.argv for that!

import sys

"""
sys.argv returns a list object containing all the arguments passed when
running your script, including the script itself.

In this case, running the command python test.py "ab,xy,py,cd,ef,gh"
will return: ['test.py', 'ab,xy,py,cd,ef,gh']

If, instead of the list of values enclosed in double quotes you pass
the individual values separated by spaces, you will get a list with
the script name plus every value you passed.

python test.py ab xy py cd ef gh
will return: ['test.py', 'ab', 'xy', 'py', 'cd', 'ef', 'gh']

Than you can get only the values you want using list comprehension:
values = sys.argv[1:]

The above gets all the values from sys.argv except the first index,
which is the script file. 
"""

arguments = sys.argv
values = arguments[1:]

print(values)