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Another one
#1
I had another problem.

SENTINEL = 0

#Function uses modulus equation to determine if number is even or not
def is_even(num):
    if num % 2 == 0:
        return True
    else:
        return False

#if this input value returns true then print
is_even_number = is_even(int(input("Enter a number: ")))
while is_even_number>SENTINEL
    if True:
        print("Even")
    is_even_number = is_even(int(input("Enter a number: ")))
    else:
        print("Odd")
    is_even_number = is_even(int(input("Enter a number: ")))
    if is_even_number==0:
        break
        print("Done!")
Error:
File "main.py", line 12 while is_even_number>SENTINEL ^ SyntaxError: invalid syntax
Reply


Messages In This Thread
Another one - by the_jl_zone - Mar-07-2023, 08:01 PM
RE: Another one - by ndc85430 - Mar-07-2023, 08:02 PM
RE: Another one - by buran - Mar-07-2023, 08:10 PM

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