How to compare two parameters in a function that has *args?

[Milan]

You are checking at the wrong time. Tell the user what they can enter and force them to enter values that are correct.

def get_number(prompt, range=None):
    """Force user to input number.  If range provided, input must be in range."""
    while True:
        try:
            value = int(input(prompt))
            if not range or range[0] <= value <= range[1]:
                return value
            print("Invalid input.  Try again")
        except ValueError:
            print("Invalid input.  Try again")


MAX_LENGTH = 30
MIN_LENGTH = 8
remaining = MAX_LENGTH - 2  # at least 1 lettter, number and special character

special = get_number(f"How many special characters (1-{remaining}): ", (1, remaining))
remaining = remaining - special + 1

if remaining > 2:
    numbers = get_number(f"How many numbers (1-{remaining}): ", (1, remaining))
else:
    numbers = 1

remaining = remaining - numbers + 1
if remaining > 1:
    min_letters = max(1, MIN_LENGTH - (special + numbers))
    letters = get_number(f"How many letters ({min_letters}-{remaining}): ", (min_letters, remaining))
else:
    letters = 1

print(letters, numbers, special)

To answer your question, you could do something like this:

def check(*args):
    """Force all args to be at least 1"""
    return [max(1, arg) for arg in args]

Thank you very much.