Need Help: Sort of Binary numbers based on 1's present

[abinashj]

I can't read your link...

codes are :

#Binary conversion
cnt_num = int(input("Enter total no of number : "))
num = []

for i in range(cnt_num):
   print("Enter numbers:[",i,"]: ",end = '')
     
   num1 = int(input())
   num.append(num1)

print("Numbers in list are : ",num)



for j in range(len(num)):
   
   bin_num.append(bin(num[j])[2:])
   
   bits = bin_num[j].count('1')
   print(num[j],bin_num[j],' count ones are : ',bits)

#Need to write logic to sort the binary numbers based on counting no of 1's