decimal or hexadecimal digits to int

[Skaperen]

The python int() function takes in a base parameter which converts to object/string to base 10 from the given base.
So int('101',2) = 5.

Here's one way you can write you program

def convertToInt(num_string):
determine_base ={'0x':16,'0b':2,'0o':8} # dict to detrmine base

# returns base from dict defaults to None(for base 10)
base = determine_base.get(num_string[:2].lower(),None)

if base != None:
return int(num_string[2:],base)
else:
return int(num_string)

# prefix '0x' & '0X' => hexadecimal, '0b' & '0B' => binary, '0O' and '0o' => Octal
strings = ['0xd4','0B10001','0o763','56']

for num in strings:
print(convertToInt(num))

something like that was what i had in mind.