How to make a dynamic variable based on input

[loltylerdowney]

Hello there, welcome to Python! It would be quite helpful if you used the python BBCode so we can better read your code, which includes all your indentation.

With that being said, this is how I would tackle it.

def grades(): # Define a function, no argument for now so just () will do
    try: # Tells python to try this
        cGrade = int(input("What is your current grade in the class? "))
        cGrade = cGrade * 4 #to fit the formula to find exam grade needed

        a = 450 - cGrade # int(cGrade) is redundant in this case, cGrade is already an interger
        b = 400 - cGrade
        c = 450 - cGrade
        d = 300 - cGrade
        
        # .upper() forces python to read the input as an uppercase letter.
        fGrade = input("What letter grade would you like to end with? ").upper()

        if fGrade == "A": # == means is-equal-to
            print("In order to end with an A, you will need to score",a,"on your final exam.")
        elif fGrade == "B":
            print("In order to end with an B, you will need to score",b,"on your final exam.")
            # To print variables you can use commas print("Word",variable,"Word.")


            # And so on

    except ValueError: # Unless the user doesn't input an integer in this case
        print("Invalid input, try again.")


grades() # Calls are grades() function so it can run

Of course, this is quite basic, you could add more functionality by using loops for example.



BBCode Tutorial

Regards,
Prrz

Thanks I ended up with two solutions, one that I figured out, and one that a friend of mine showed to me. Turns out a dictionary was the way to go lol